What is the multiplication of 67th and 68th term in the sequence 3, 4, 2, 1, 3, 4, 2, 1, 3, 4…......?

Is it possible to solve with mod arithmetic? So, sequence starts over every 4 numbers, so take mod 4. Then, 67 is equivalent to 3 (mod 4) and 68 is equivalent to 0 (mod 4). So we have 1(3)=3?

This seems off to me.