Given that A^X + B^Y = C^Z, where A, B, C > 0 and X, Y, Z >2 what is the reason that Z < 2*max(XlogA, YlogB)??
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Originally Posted by chauhan Given that A^X + B^Y = C^Z, where A, B, C > 0 and X, Y, Z >2 what is the reason that Z < 2*max(XlogA, YlogB)?? WLOG and suppose as
I dont understand how this answers the question. I remember the idea was to show that Z < 2*XlogA and Z < 2*YlogB and so Z<2*max(XlogA, YlogB). chiph588@, I dont see how XlogA > YlogB. Nor do I understand how A^X + B^Y is equal to
Originally Posted by chauhan I dont understand how this answers the question. I remember the idea was to show that Z < 2*XlogA and Z < 2*YlogB and so Z<2*max(XlogA, YlogB). chiph588@, I dont see how XlogA > YlogB. Nor do I understand how A^X + B^Y is equal to I just assumed one was bigger than the other. Also .
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