if , then

Not sure how to prove this.

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- June 27th 2010, 01:16 PMdwsmithif a^2 \equiv 1, then a \equiv \pm 1 (mod p)
if , then

Not sure how to prove this. - June 27th 2010, 02:15 PMjamix
Well if and only if so.....

- June 27th 2010, 02:17 PMdwsmith
I wasn't sure if I could assume the mod p in if part because it wasn't written in the book.

- June 27th 2010, 02:22 PMBruno J.
Also : in general, a polynomial of degree has at most roots . In this case, we know are two roots, so there can't be any others.

- June 27th 2010, 03:41 PMmathman88
- June 27th 2010, 03:43 PMdwsmith