, then .

Is this all there is to this one:

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- June 26th 2010, 04:46 PMdwsmitha \not\equiv b (mod m), then b \not\equiv a (mod m)
, then .

Is this all there is to this one:

- June 26th 2010, 05:12 PMAckbeet
If your other congruence post is logically prior to this one, then it looks good. Otherwise, you should interpose, twice, the intermediate step AsZ showed in the other post. Just for completeness.

- June 26th 2010, 05:14 PMdwsmith
In the book, it defines .

The problem is it justed seemed to easy to be true though. - June 26th 2010, 05:16 PMAckbeet
Oh, ok. Different authors define congruence differently, I guess.

- June 26th 2010, 06:21 PMchiph588@
You have the right idea.

- July 5th 2010, 02:44 AMmelese