Thread: [SOLVED] Binary divsion

I keep getting 101 which is wrong. How do I do this problem then?

Originally Posted by dwsmith

I keep getting 101 which is wrong. How do I do this problem then?

Exactly as you do decimal division: take the first three digits in the first number (110), then 101 fits once in it, so multiply 101 times 1, put below 110 and substract:

110
-
101
----
001

Next bring down the next digit, 0: as 0010=10 is less than the divisor 101, we put a zero besides the 1 in the quotient and bring down 1, and etc.

At the end you get 1010, which is correct: 110101 (53) divided by 101(5) equals 1010 (10) and gives a residue of 11 (3).

Tonio

Hello, dwsmith!

Tonio is absolutely correct.

The division looks like this:


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