Could you please help me with this question:

Find all positive integersNsuch that the product 2005 *Nhas exactly six divisors.

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- Apr 28th 2005, 06:18 PMmathsmaddivisors
Could you please help me with this question:

Find all positive integers*N*such that the product 2005 **N*has exactly six divisors. - Apr 28th 2005, 09:53 PMMath Help
5 * 401 = 2005

5*401*2*2*2*2 = 2005*16

5*401*2*2*2*3 = 2005*24

5*401*2*2*2*5 = 2005*60

this could go on forever. Ther are infinites N's where this would work. - Apr 29th 2005, 06:47 PMhpeCorrected solutionQuote:

Originally Posted by**Math Help**

Try M = 5: Then 1, 5, 25, 401, 2005, 10025 are the only divisors of 2005*5.

M = 401 also works.

If M has any prime factor other than 5 or 401, let's say p, there will be at least seven divisors: 1, 5, 401, p, 5p, 401p, 2005p.

If M is a power of 5 or has divisors 5 and 401, there will also be too many divisors. - May 14th 2005, 07:46 PMmathsmadThanks for the help
Thanks for the help

- Aug 27th 2005, 12:01 AMvingtaCheat!!
Cheater!!!!!

Your suppose to do the Euler questions by yourself. Just look at thus website, http://www.amt.edu.au/mcya.html,

You CHEAT!!!! :mad: