Hi, I've got so far try to solve simultaneous congruence equations but have run a ground.
Question is solve the simultaneous equations
7x = 3mod34 and x=7mod41
I've solved the first one to get x= 15mod 34 hence x= 34u+15
The second is x= 7 mod 41
Thus I've put 34u+15 = 7mod 41
Now at this point I thought it would go to 34u = 33mod41 but if this is the case then I'm struggling to solve for u. I think I've made a mistake at 34u+15 = 7 mod 41 but not sure what.