Hello!

I conjectured today that is true for every integer, where is giving the sum of digits in base 3.

Has it already solved or hard to proof?

Ben

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- May 12th 2010, 11:12 AMBen92Sum of digits in base 3
Hello!

I conjectured today that is true for every integer, where is giving the sum of digits in base 3.

Has it already solved or hard to proof?

Ben - May 12th 2010, 04:21 PMundefined
Hi, Ben92,

I must have misinterpreted what you wrote. I wrote a program that determined three sequences:

: 1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768, ...

(in base 3): 1, 2, 11, 22, 121, 1012, 2101, 11202, 100111, 200222, 1101221, 2210212, 12121201, 102020102, 211110211, 1122221122, ...

: 1, 2, 2, 4, 4, 4, 4, 6, 4, 8, 8, 10, 10, 8, 10, 16, ...

The third sequence is the sum of digits of the corresponding member in the second sequence.

Could you clarify the meaning?