Hi, p is a positive prime number. How to show that there isn't any pair(a;b) from $\displaystyle \mathbb{N}^2$* such as $\displaystyle a^2=pb^2$
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Originally Posted by bhitroofen01 Hi, p is a positive prime number. How to show that there isn't any pair(a;b) from $\displaystyle \mathbb{N}^2$* such as $\displaystyle a^2=pb^2$ Hint: Express $\displaystyle a $ and $\displaystyle b $ as a product of prime numbers and look at the exponent's parity.
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