how do I write -8i in polar form?

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- Apr 28th 2010, 04:36 AMtim_mannirecomplex number polar form
how do I write -8i in polar form?

- Apr 28th 2010, 04:56 AMtonio
- Apr 28th 2010, 05:20 AMtim_mannire
z^3 = -8i . Does the polar form change for z^3 = -8i

- Apr 28th 2010, 05:57 AMraheel88
Solving ...so u want to solve for z right?

If you write z as and substitute this into and solve.

You get r = 2 and .

Therfore - Apr 28th 2010, 06:04 AMtim_mannire
- Apr 28th 2010, 07:04 AMraheel88