This is a 4 part question on my tutorial and if you prove part d) the rest follow, except there's no part d) in the question! I can prove a), b) and c) without using whatever d) is but just thought I'd see if you guys know what this proof is actually proving!
Q. Let p be an odd prime, and a, b be integers not divisible by p. Prove that
a) a \equiv b (mod p) implies that
b).
c);
.
(I though perhaps part d) was the second equality in part c) but I don't think the proof matches up.
PROOF.
a), b) and c) follow from d) so we should prove that first!
d) Take a primitive root g, withmod
.
Then.
Asmod
we see that...
mod
if
is even (i.e if a is a quadratic residue),
whilemod
if
is odd (i.e a non quadratic residue). Hence result.
I was thinking it was probably something like show that if g is a primitive root and k is even then,
. and if k is odd then ... = -1.


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