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Thread: Divisibility

  1. #1
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    Divisibility

    The Division Algorithm says that $\displaystyle m=nq+r$, where $\displaystyle 0\leq r < n, n \geq 2$.

    I understand that when $\displaystyle r=0$, $\displaystyle m $ is a multiple of n, or $\displaystyle m$ is divisible by n.

    Technically, we say when $\displaystyle m=0$ and $\displaystyle r=0, n|0$.

    Now, my question is this: When we divide $\displaystyle 0$ by $\displaystyle n$, we really have nothing to divide, but why $\displaystyle n|o$? Could anyone explain?
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  2. #2
    MHF Contributor chiph588@'s Avatar
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    0=0*n
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  3. #3
    MHF Contributor Drexel28's Avatar
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    Quote Originally Posted by chiph588@ View Post
    0=0*n
    $\displaystyle 0=0n+0$ :P
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  4. #4
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    Quote Originally Posted by Drexel28 View Post
    $\displaystyle 0=0n+0$ :P
    Naughty
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