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Math Help - lcm

  1. #1
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    lcm

    Peter makes $84/sale that he makes. If he buys stock in a company at $160/share, what is the minimum number of shares purchased?
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  2. #2
    Super Member Deadstar's Avatar
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    Can you type the full question out? What you've wrote doesn't seem to make any sense or there's some info missing.

    But for your info, the least common multiple of 84 and 160 is...

    \frac{84 \cdot 160}{\gcd(84,160)} = \frac{13440}{2} = 6720
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  3. #3
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    sorry...all of his profits must be used.

    the lcm is 3360
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  4. #4
    Super Member Deadstar's Avatar
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    Quote Originally Posted by ihavvaquestion View Post
    sorry...all of his profits must be used.

    the lcm is 3360
    Oops so it is. Can you just type out the actual question IN FULL!
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  5. #5
    Super Member Deadstar's Avatar
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    Does he but a stock for 160, sell it and get 84 profit? Then he reinvests his profit into buying more stock?
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  6. #6
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    Peter sells carborators. He makes $84 on each carborator. Using ALL his profits from the sale of these carborators, he buys several shares of stock at $160/share. What is the minimum number of shares of stock that he could have purchased?
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  7. #7
    Super Member Deadstar's Avatar
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    Quote Originally Posted by ihavvaquestion View Post
    Peter sells carborators. He makes $84 on each carborator. Using ALL his profits from the sale of these carborators, he buys several shares of stock at $160/share. What is the minimum number of shares of stock that he could have purchased?
    least common multiple of 84 and 160 divided by 160. 3360/160 = 21.
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  8. #8
    Super Member Bacterius's Avatar
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    Quote Originally Posted by Deadstar View Post
    Can you type the full question out? What you've wrote doesn't seem to make any sense or there's some info missing.

    But for your info, the least common multiple of 84 and 160 is...

    \frac{84 \cdot 160}{\gcd(84,160)} = \frac{13440}{2} = 6720
    \gcd(84, 160) = 4
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  9. #9
    Super Member Deadstar's Avatar
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    Quote Originally Posted by Bacterius View Post
    \gcd(84, 160) = 4
    lol yeah I noticed that but OP had already corrected it. Fixed it for my answer though.
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