Thread: solving a system of simultaneous linear congruent equations..

Hi please help me in solving this,

25=4x+y(mod 26) {25 is congruent to (4x+y) modulo 26}
3=19x+y(mod 26)
where gcd (x,26)=1

or
25=4x+y(mod 26)
24=19x+y(mod 26)
where gcd (x,26)=1

Thanks in advance...

Originally Posted by strings

Hi please help me in solving this,

25=4x+y(mod 26) {25 is congruent to (4x+y) modulo 26}
3=19x+y(mod 26)
where gcd (x,26)=1

or
25=4x+y(mod 26)
24=19x+y(mod 26)
where gcd (x,26)=1

Thanks in advance...

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