Hi please help me in solving this, 25=4x+y(mod 26) {25 is congruent to (4x+y) modulo 26} 3=19x+y(mod 26) where gcd (x,26)=1 or 25=4x+y(mod 26) 24=19x+y(mod 26) where gcd (x,26)=1 Thanks in advance...
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Originally Posted by strings Hi please help me in solving this, 25=4x+y(mod 26) {25 is congruent to (4x+y) modulo 26} 3=19x+y(mod 26) where gcd (x,26)=1 or 25=4x+y(mod 26) 24=19x+y(mod 26) where gcd (x,26)=1 Thanks in advance... Theorem: and
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