LinkBack URL
About LinkBacks(k/k+1)+ (1/(k+1)(k+2)) = (k+1)/(k+1)+1
I just need to make the left side equal to the right side. This is what I have:
k(k+2)/(k+1)(k+2) + 1/(k+1))k+2) =(k+1)/(k+1)+1
k(k+2)+1/(k+1)(k+2) = (k+1)/(k+1)+1
.Originally Posted by math61688
(k/k+1)+ (1/(k+1)(k+2)) = (k+1)/(k+1)+1
The right side must be, but then:
(k+2)}=\frac{1}{k+1}\l eft(k+\frac{1}{k+2}\right)=\frac{1}{k+1}\left(\fra c{k^2+2k+1}{k+2}\right))
Tonio
I just need to make the left side equal to the right side. This is what I have:
k(k+2)/(k+1)(k+2) + 1/(k+1))k+2) =(k+1)/(k+1)+1
k(k+2)+1/(k+1)(k+2) = (k+1)/(k+1)+1
  |
