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Math Help - Limits, least value of N

  1. #1
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    Limits, least value of N

    How can I find the value of n such that (4n-2)/(7n-3) is within 10^-2 of its limit 4/7 . I know you set (4n-2)/(7n-3)-4/7 < 10^-2 but I can seem to rearrange it, thanks
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  2. #2
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    Quote Originally Posted by jpquinn91 View Post
    How can I find the value of n such that (4n-2)/(7n-3) is within 10^-2 of its limit 4/7 . I know you set (4n-2)/(7n-3)-4/7 < 10^-2 but I can seem to rearrange it, thanks
    Hi jpquinn91,

    You will need to write the difference the other way around.

    \frac{4}{7}-\frac{4n-2}{7n-3}<10^{-2}

    4(7n-3)-7(4n-2)<7(7n-3)10^{-2} if 7n>3

    28n-12-28n+14<(49n-21)10^{-2}

    200<49n-21

    49n>221

    n>\frac{221}{49}

    n=5 or so.

    \frac{4}{7}-\frac{18}{32}=0.00892
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