I cannot see why the folowing is correct: where is the Mobius function....
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Originally Posted by bigdoggy I cannot see why the folowing is correct: where is the Mobius function.... well, by the Euler product formula or just a simple observation we have: where the product is over all (distinct) primes. thus by the definition of and after expanding the product.
Originally Posted by bigdoggy I cannot see why the folowing is correct: where is the Mobius function.... If s > 1,
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