Given that gcd(a,b,c)lcm(a,b,c) = abc, prove that gcd(a,b)=gcd(b,c)=gcd(a,c)=1.

How can we prove this?

Any help is appreciated.

[also under discussion in math link forum]

Results 1 to 1 of 1

- Feb 23rd 2010, 09:37 AM #1

- Joined
- Jan 2009
- Posts
- 405

Click on a term to search for related topics.