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Thread: sum of divisor

  1. February 10th 2010, 12:20 PM #1
    ha11
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    sum of divisor

    How can prove
    σ(n)=Σd<Σ1\d

    where σ(n) maen sum of divisor
    The index of first Σ is d|n and the second Σ is d<n
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  2. February 10th 2010, 03:02 PM #2
    Drexel28
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    Quote Originally Posted by ha11 View Post
    How can prove
    σ(n)=Σd<Σ1\d

    where σ(n) maen sum of divisor
    The index of first Σ is d|n and the second Σ is d<n
    This makes no sense. You're claiming that \sum_{d\mid n}d<\sum_{d<n}\frac{1}{d}?
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