How can prove

σ(n)=Σd<Σ1\d

where σ(n) maen sum of divisor

The index of first Σ is d|n and the second Σ is d<n

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- February 10th 2010, 12:20 PMha11sum of divisor
How can prove

σ(n)=Σd<Σ1\d

where σ(n) maen sum of divisor

The index of first Σ is d|n and the second Σ is d<n - February 10th 2010, 03:02 PMDrexel28