Now we need to find the last two digits in , and the problem is solved.
The given number is divisible by 4, hence its last two digits are multiples of 4.
So the digits are either 04,08,12,16,......96.
We can see that the last digit in clearly is 8.
Now since the above number is divisble by four, the, possible values for the last two digits are 08,28,48,68,88.
Now, consider the powers of 2 which have the last digit 8
We can see, that the digits 08,28,48,68,88 repeat at regular intervals
Hence, we can obtain the last two digits in the number
which are 88
So the last two digits in the number are the last two digits in the number 63X88,