Now we need to find the last two digits in , and the problem is solved.

The given number is divisible by 4, hence its last two digits are multiples of 4.

So the digits are either 04,08,12,16,......96.

We can see that the last digit in clearly is 8.

Now since the above number is divisble by four, the, possible values for the last two digits are 08,28,48,68,88.

Now, consider the powers of 2 which have the last digit 8

8

128

2048

32768

524288

8388608

We can see, that the digits 08,28,48,68,88repeat at regular intervals

Hence, we can obtain the last two digits in the number

which are 88

So the last two digits in the number are the last two digits in the number 63X88,

i.e. 44