Here is the problem. Let n be a positive integer, not = 1, and not prime, prove n has a divisor d such that 1<d<sqrt(n)

The way i began attacking this was by saying n is either even or odd. If n is even and not prime then n >= 4 and 2|any even integer and 1<2<sqrt(4). They problem im having is on the odd case there is no number like 2 that will divide all odd numbers so i dont know how to show a divisor would fall in this interval