some one has x pices of gold.he wants to distibute them in groups in such a way that each group contain equal number of pices.
when he put 2 pices in each group 1 piece remained.same happened when he put 3,4,5,6,7,8,9,10.each time 1 piece is remained.
But when he put 11 pieces in each group.no piece is remained.how many iron pieces are there???:mad:
Mar 7th 2007, 08:37 PM
Solve (by Chinese Remainder Theorem)
x=1 (mod 2)
x=1 (mod 3)
x=1 (mod 5)
x=1 (mod 7)
And among those solutions find one that is divisible by 11.
Mar 13th 2007, 06:46 PM
Thanks Perfecthacker .i solved it and it comes out 25201.