How would I find the smallest number n such that tau(n)=1001 tau(n) is the number of possible divisors of a positive number, n
Last edited by MichaelG; Dec 15th 2009 at 12:36 PM.
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Given , . Therefore , , . Now pair the smallest prime with the largest , the second smallest prime with the second larget , and the third smallest prime with the smallest . Hence .
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