Show (23^(37)+15^(16)) is congurent to 5 (mod 18). Not sure how to do this need some help please!!
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Originally Posted by steph3824 Show (23^(37)+15^(16)) is congurent to 5 (mod 18). Not sure how to do this need some help please!! I did it two ways and I get something different. The following is done modulo 18: Of course, I could be wrong... Tonio
Originally Posted by steph3824 Show (23^(37)+15^(16)) is congurent to 5 (mod 18). Not sure how to do this need some help please!! & That agrees with tonio.
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