Note that a_2*10^2 = 99 + 1 and a_1*10 = (11 - 1), etc.
Thus, it should be obvious from this that just adding and subtracting consecutive terms will determine if the number is div. by 11. With palindromes, since you're adding and subtracting the same number of digits, it will = 0, and thus will be divisible by 11.
February 25th 2007, 07:10 PM
Originally Posted by lyla
Any help would be appreciated on the following.
A palindrome is a number that reads same backwards as fowards (for instance, 373 and 521125 are palindromes). Prove that any palindrome with an even number of digits is divisible by 11.