When $\displaystyle n=2009$, find the remainder when

$\displaystyle \frac{11 \times 10^n - 4 \times 3^n}{99}$.

Have no idea how to approach this problem, any help would be appreciated ;)

I've got the hint that $\displaystyle 99 = 11 \times 9$, thinking that the solutions involves $\displaystyle (mod 11)$ and $\displaystyle (mod 9)$?

Thanks in advance for the help

Craig