evaluate legender symbol ( 2 / 2^43112609 - 1) ie ( 2/largest prime)
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There is no largest prime. Use the fact that for and for .
Out of curiosity, how would you evaluate linear congruences like if you have BIG numbers, without a calculator or computer?
If (mod c), then (mod c), I guess ?
Originally Posted by ilikecandy Out of curiosity, how would you evaluate linear congruences like if you have BIG numbers, without a calculator or computer? Think about it : for . So .
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