Results 1 to 2 of 2

Thread: Help finding the decryptor

  1. #1
    Oct 2009

    Help finding the decryptor

    If Z(w) is equivalent to 21w+12 and this is an encryptor, then how would I find the decryptor?

    I know the decryption law is w=A^(-1) * (Z-B) (mod N) where A^(-1) is the multiplicative inverse.

    The encryption law is E(w) is equivalent to Aw + B (mod N)
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor chisigma's Avatar
    Mar 2009
    near Piacenza (Italy)
    Under the hypothesis that N=26 , if A=21 then 21 \cdot 5= 105 = 1 \mod 26 \rightarrow A^{-1}=5, so that the decription law will be...

     w= 5 \cdot (Z-12) \mod 26 (1)

    Kind regards

    \chi \sigma
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 10
    Last Post: Dec 8th 2011, 11:27 AM
  2. Replies: 1
    Last Post: Jul 3rd 2010, 11:40 PM
  3. Finding a limit. Finding Maclaurin series.
    Posted in the Calculus Forum
    Replies: 2
    Last Post: May 18th 2010, 11:04 PM
  4. Finding the radius, solving, and finding theta?
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: Jun 13th 2009, 03:37 PM
  5. Replies: 1
    Last Post: Apr 9th 2009, 10:02 AM

Search Tags

/mathhelpforum @mathhelpforum