Let x be an ODD integer show that for n>=3
x^2^(n-2) is congruent to 1 (mod 2^n)
Sorry about the superscripts I dont use the computer for math often.
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It holds for ; I'll let you prove that. Suppose it holds up to . Note that ; and by the induction hypothesis, is divisible by , and since is odd, is divisible by 2 so is divisible by .
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