1. Is there such number N that 7 divided N^2=3?
Isnt it just root of 7/3?
2. x^2 + y^2 = z^2. Prove xyz is a multiple of 60
Not sure what to do here, and where to get the xyz term from
Printable View
1. Is there such number N that 7 divided N^2=3?
Isnt it just root of 7/3?
2. x^2 + y^2 = z^2. Prove xyz is a multiple of 60
Not sure what to do here, and where to get the xyz term from
1)
I assume you mean 7 divided by n^2 = 3
If you're dealing with divisibility in number theory, I think the question may be asking if there is an integer which divides 7 giving the quotient 3. This would mean that 7 would have 3 as a factor. 7, being prime, has no factors.
However the root of 7/3 does does yield a quotient of 3. The number does exist (root of 7/3), but it is not an integer.
2.Quote:
Originally Posted by Aquafina
The solution set is.
. Thus xyz is a multiple of 60.
so what about the set (5,12,13)?Quote:
Originally Posted by alexmahone2.
The solution set is
You've got to try the following:
Prove that one of the numbers are divisble by 5,
prove that one of them is divisible by 3
and prove that one of them i divisible by 4.
These statements are true and should not be to hard to prove.