show that if an integer n has at least two distinct odd prime divisors then there exists k<φ(n) such that
a^k ≡ 1(mod n)for every a relatively prime to n.
What I have so far: The expression a^k ≡ 1(mod n) looks similar to Euler's Generalization of Fermat's Little Theorem. Also, n can be expressed as xp1p2, where x is a positive integer, and p1 and p2 are odd distinct prime numbers.
I know this isn't much, but I don't to where to go afterwards to complete the proof.