Find all n such that:
The is a multiplicative function so that if m and n are coprime, then...
(1)
For and is and is an even number, so that the solutions of the equation...
(2)
... are obtained by systematic search of couples of coprime numbers m and n for which is...
(3)
Since solutions are...
Since also solutions are...
Finally is so that solution is...
The numbers k for which is are...
Kind regards
Hi, thank you for directing me here. Its good to see an example, but i dont understand this method.
Why do you multiply 7 by 3, 4 and 6? And how do you get and . I know you can easily work these out but aren't both of these just an instance of the same sort of question as ? Aren't there more ?
Sorry if i'm being a bit slow, all this is very confusing for me.
The basic assumptions are...
a) is only for and . For all , is an even number...
b) is if and only if m and k are coprime...
On the basis of b) the identification of an n for which is for the fact that must be where m and k are coprime and . There are the following possibilities...
,
,
The situation...
,
... as proposed by tonio in the original post, is impossible on the basis of a)...
Kind regards