What two-digit integer is six times the sum of its digits?
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Originally Posted by sri340 What two-digit integer is six times the sum of its digits? Solve this by setting up the equation: where a and b are the number's two digits. There's only a limited number of integral solutions, and you'll (probably) find that only one of those has both a and b in single digits. Give it a play, see what happens.
Originally Posted by sri340 What two-digit integer is six times the sum of its digits? If xy is the two digit number and x+y is the sum of the digits: 10x+y = (x+y)6 10x + y = 6x +6y 4x = 5y Only two numbers satisify that
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