I think this goes here.

I'm not sure where to start with this proof, rather i'm not sure where to start with this proof if I do not use the fact that I can square both sides.

because I think:

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- Sep 8th 2009, 07:34 PMseld[SOLVED] relation question
I think this goes here.

I'm not sure where to start with this proof, rather i'm not sure where to start with this proof if I do not use the fact that I can square both sides.

because I think: - Sep 8th 2009, 07:47 PMBruno J.
If then .

Now , hence and you have it.

(Note that in LaTeX, \in = and \epsilon = ) - Sep 8th 2009, 08:06 PMseld
It took me a while to figure out the latex thing i've never used it before.

Though I'm not sure I'm allowed this fact

for |x|<1

I know I'm allowed to use:

So I guess in essence I need to prove for - Sep 8th 2009, 08:10 PMBruno J.
You have . Multiply by on both sides and you have . Take the square root on both sides and you have .

- Sep 8th 2009, 08:31 PMseld
thank you for both help with this and the latex