Hello, could somebody solve this to find the values for P_{1 }and P_{2} for me and show how they have worked it out I am struggling a bit with it. Thanks
2P_{1 - }5P_{2 }= -6
-P_{1 }+ 3P_{2 }= 4
Another way: from $\displaystyle -P_1+ 3P_2= 4$ adding $\displaystyle P_1$ to both sides gives $\displaystyle 3P_2= 4+ P_1$ and then subtracting 4 from both sides gives $\displaystyle 3P_2- 4= P_1$. Now, we can replace $\displaystyle P_1$ with $\displaystyle 3P_2- 4$ in $\displaystyle 2P_1- 5P_2=- 6$: $\displaystyle 2(3P_2- 4)- 5P_2= 6P_2- 8- 5P_2= P_2- 8= -6$ so $\displaystyle P_2= 8- 6= 2$. Then $\displaystyle P_1= 3P_2- 4= 3(2)- 4= 6- 4= 2$.