# Thread: how to solve this

1. ## how to solve this

write this fraction in descending order 7/9, 2/3,5/12 ,1/6 pls how to solve this

2. ## Re: how to solve this

Hey yuri2006.

Hint - If you have two numbers a/b and c/d then ad > bc if a/b > c/d [and b, d are non-zero and positive numbers].

3. ## Re: how to solve this

Originally Posted by yuri2006
write this fraction in descending order 7/9, 2/3,5/12 ,1/6 pls how to solve this
you can use Chiro's method or you could convert all the fractions to a common denominator.

In this case it looks like 36 will be the least common multiple of all the denominators shown.

So just multiply the numerator of each by (36/denominator)

for example $\dfrac 7 9 \to \dfrac{\frac{36}{9}\cdot 7}{36} = \dfrac{28}{36}$

once you convert all the fractions shown to have denominator 36 it will be trivial to order them.

4. ## Re: how to solve this

First, change the fractions to a common denominator

$\dfrac{7}{9}=\dfrac{28}{36}$

$\dfrac{2}{3}=\dfrac{24}{36}$

$\dfrac{5}{12}=\dfrac{15}{36}$

$\dfrac{1}{6}=\dfrac{6}{36}$

Now, write the following fractions in descending order according to numerator-

So, $\dfrac{28}{36}<\dfrac{24}{36}< \dfrac{15}{36} < \dfrac{6}{36}$

Therefore, $\dfrac{7}{9}<\dfrac{2}{3}<\dfrac{5}{12}<\dfrac{1} {6}$

5. ## Re: how to solve this

Originally Posted by deesuwalka
First, change the fractions to a common denominator

$\dfrac{7}{9}=\dfrac{28}{36}$

$\dfrac{2}{3}=\dfrac{24}{36}$

$\dfrac{5}{12}=\dfrac{15}{36}$

$\dfrac{1}{6}=\dfrac{6}{36}$

Now, write the following fractions in descending order according to numerator-

So, $\dfrac{28}{36}<\dfrac{24}{36}< \dfrac{15}{36} < \dfrac{6}{36}$

Therefore, $\dfrac{7}{9}<\dfrac{2}{3}<\dfrac{5}{12}<\dfrac{1} {6}$
Hey deesuwalka, your inequality signs are pointing the wrong way!

6. ## Re: how to solve this

Ohh, sorry I mistakenly typed. Thanks