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Thread: how to solve this

  1. #1
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    Unhappy how to solve this

    write this fraction in descending order 7/9, 2/3,5/12 ,1/6 pls how to solve this
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  2. #2
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    Re: how to solve this

    Hey yuri2006.

    Hint - If you have two numbers a/b and c/d then ad > bc if a/b > c/d [and b, d are non-zero and positive numbers].
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  3. #3
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    Re: how to solve this

    Quote Originally Posted by yuri2006 View Post
    write this fraction in descending order 7/9, 2/3,5/12 ,1/6 pls how to solve this
    you can use Chiro's method or you could convert all the fractions to a common denominator.

    In this case it looks like 36 will be the least common multiple of all the denominators shown.

    So just multiply the numerator of each by (36/denominator)

    for example $\dfrac 7 9 \to \dfrac{\frac{36}{9}\cdot 7}{36} = \dfrac{28}{36}$

    once you convert all the fractions shown to have denominator 36 it will be trivial to order them.
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  4. #4
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    Re: how to solve this

    First, change the fractions to a common denominator

    $\dfrac{7}{9}=\dfrac{28}{36}$

    $\dfrac{2}{3}=\dfrac{24}{36}$

    $\dfrac{5}{12}=\dfrac{15}{36}$

    $\dfrac{1}{6}=\dfrac{6}{36}$

    Now, write the following fractions in descending order according to numerator-

    So, $\dfrac{28}{36}<\dfrac{24}{36}< \dfrac{15}{36} < \dfrac{6}{36}$

    Therefore, $\dfrac{7}{9}<\dfrac{2}{3}<\dfrac{5}{12}<\dfrac{1} {6}$
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  5. #5
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    Re: how to solve this

    Quote Originally Posted by deesuwalka View Post
    First, change the fractions to a common denominator

    $\dfrac{7}{9}=\dfrac{28}{36}$

    $\dfrac{2}{3}=\dfrac{24}{36}$

    $\dfrac{5}{12}=\dfrac{15}{36}$

    $\dfrac{1}{6}=\dfrac{6}{36}$

    Now, write the following fractions in descending order according to numerator-

    So, $\dfrac{28}{36}<\dfrac{24}{36}< \dfrac{15}{36} < \dfrac{6}{36}$

    Therefore, $\dfrac{7}{9}<\dfrac{2}{3}<\dfrac{5}{12}<\dfrac{1} {6}$
    Hey deesuwalka, your inequality signs are pointing the wrong way!
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  6. #6
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    Re: how to solve this

    Ohh, sorry I mistakenly typed. Thanks
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