$x^3-9x^2+27x-27$

well we know that $(-3)^3-=-27$ so let's try $x-3$ as a factor

$\dfrac{x^3-9x^2+27x-27}{x-3}=x^2-6x+9$

and it's fairly easily recognized that

$x^2-6x+9=(x-3)^2$

so

$x^3-9x^2+27x-27=(x-3)^3$

So this is basically $x^3$ but shifted over 3 to the right. You should be able to draw a quick sketch of $x^3$.

Do this but center it at $x=3$