no of possible outcomes=6*6=36

now if white die sets 1 then red die has 2,3,4,5,6=5

white die sets 2 red die has 3,4,5,6=4

white die sets 3 red die has 4,5,6=3

white die sets 4 red die has 5,6=2

white die sets 5 red die has 6=1

now prob=(5+4+3+2+1)/36=5/12