Factor.
(x-4)^3 + (x+4)^3

I need help on this question, i have a test tommorow, thanks in advance!

Multiply it out. Then, you will have two terms, one will have an $x^3$ and one will have an $x$. You will be able to factor out 2x.

thanks for the reply, but when i multiply it out i get x^3-64+x^3+64. What do you mean by two terms?

I was wondering if we are supposed to use the formulas :
x^3 - y^3 = (x-y)(x^2 + xy + y^2)
x^3 + y^3 = (x+y)(x^2 - xy + y^2)

$(x-4)^3 = (x-4)(x-4)(x-4) = x^3-12x^2+48x-64$
$(x+4)^3 = (x+4)(x+4)(x+4) = x^3 + 12x^2 + 48x + 64$
Add them together and you get the two terms I was talking about: $2x^3+96x$