A mass of 0.3 kg is suspended from a spring of stiffness 200 N m–1. If

the mass is displaced by 10 mm from its equilibrium position and

released, for the resulting vibration, calculate:

(a) (i) the frequency of vibration. For this I got 4.1 Hz

(ii) the maximum velocity of the mass during the vibration. I got 0.2582ms^-1 or 0.26ms^-1 (whichever you prefer)

(iii) the maximum acceleration of the mass during the vibration. I got 6.667ms^-2 or 6.7ms^-2 (whichever you prefer)

(iv) the mass required to produce double the maximum velocity. I don't know how to solve this and would like a little help please.....

calculated in (ii) using the same spring and initial deflection.

(b) Plot a graph of acceleration against displacement (x) (for values ofx

fromx= –10 mm tox= +10 mm). And like wise not sure how to go about this either. Could someone confirm my other answers are correct also please for peace of mind......