Results 1 to 6 of 6
Like Tree1Thanks
  • 1 Post By DavidB

Math Help - Finding the distance of two triangles at .25 degrees

  1. #1
    Newbie
    Joined
    Jun 2013
    From
    Riverside
    Posts
    6

    Finding the distance of two triangles at .25 degrees

    Hi I needed some help with some trig. I need to find the distance of both triangles A and B at a .25 degrees, and then find the distance of AB. If some one can help me out step by step with the formula on how to accomplish this would be most appreciated thanks you.
    untitled.bmp
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Jun 2013
    From
    Riverside
    Posts
    6

    Re: Finding the distance of two triangles at .25 degrees

    Any body have an idea how to solve this problem?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Sep 2006
    From
    Between my ears
    Posts
    70
    Thanks
    12

    Re: Finding the distance of two triangles at .25 degrees

    Are you sure that is supposed to be 0.25 degree? Not radians?

    You could start by calculating the difference in height between A and B and create a small triangle for the difference: A - B = 0.2325 - 0.21 = 0.0225.
    Since the angle is the same, a, you know tan(a) = 0.0225/cos(a).
    Thanks from topsquark
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    Joined
    Oct 2009
    Posts
    5,540
    Thanks
    780

    Re: Finding the distance of two triangles at .25 degrees

    Quote Originally Posted by DavidB View Post
    Since the angle is the same, a, you know tan(a) = 0.0225/cos(a).
    This is an approximate formula, isn't it? And why involve cos(a)?

    AB = (A - B)cot(a).
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Jun 2013
    From
    Riverside
    Posts
    6

    Re: Finding the distance of two triangles at .25 degrees

    DavidB/emokarov thank you for the the response was trying to work out the problem but got 80 percent complete and got stuck. Can you look at my problem and see what am doing wrong? I've exhausted the attempt to find the distance of AB. thanks
    Attached Thumbnails Attached Thumbnails Finding the distance of two triangles at .25 degrees-untitled-3.bmp  
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor
    Joined
    Oct 2009
    Posts
    5,540
    Thanks
    780

    Re: Finding the distance of two triangles at .25 degrees

    There is no need to use the right triangle calculator to find 48.128. You can find cot(0.25) = 1/tan(0.25) using a regular calculator. Anyway, you are correct, cot(0.25) = 229.18. Then, as I said in post #4, AB = (A - B)cot(a) = 0.0225 * 229.18 = 5.16 (rounding to 2 d.p.).
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Finding a formula for degrees measurements
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: November 12th 2011, 07:30 AM
  2. Replies: 2
    Last Post: February 9th 2009, 06:16 PM
  3. Finding the degrees between two headings
    Posted in the Math Topics Forum
    Replies: 4
    Last Post: November 19th 2008, 02:04 PM
  4. Replies: 7
    Last Post: March 10th 2008, 06:02 AM
  5. Need help finding an angle in degrees
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: January 19th 2007, 08:06 AM

Search Tags


/mathhelpforum @mathhelpforum