Any body have an idea how to solve this problem?
Hi I needed some help with some trig. I need to find the distance of both triangles A and B at a .25 degrees, and then find the distance of AB. If some one can help me out step by step with the formula on how to accomplish this would be most appreciated thanks you.
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Are you sure that is supposed to be 0.25 degree? Not radians?
You could start by calculating the difference in height between A and B and create a small triangle for the difference: A - B = 0.2325 - 0.21 = 0.0225.
Since the angle is the same, a, you know tan(a) = 0.0225/cos(a).
DavidB/emokarov thank you for the the response was trying to work out the problem but got 80 percent complete and got stuck. Can you look at my problem and see what am doing wrong? I've exhausted the attempt to find the distance of AB. thanks
There is no need to use the right triangle calculator to find 48.128. You can find cot(0.25) = 1/tan(0.25) using a regular calculator. Anyway, you are correct, cot(0.25) = 229.18. Then, as I said in post #4, AB = (A - B)cot(a) = 0.0225 * 229.18 = 5.16 (rounding to 2 d.p.).