
Root finding
Please help..thanks
1. Using Newton's Method, find a numerical approximation to the Zero of
F(x) = e^(x/3)  0.05471*x
on [2.5,2.9] starting with the endpoint (k = 0) having the smallest value of f,
keeping track of the number of ALL function evaluations kfe, the current
Change in sign interval [a_k,b_k], and tabulating
K kfe a_k b_k x_k f_k f_k' x_{k+1} x_{k+1}x_k
0
... ...
until x_{k+1}x_k < 0.5e2.
for k = 0 to 3 iterations.

Re: Root finding for
Do you know what "Newton's method" is?
Newton's method, for solving an equation of the form f(x)= 0 is to start with some initial "guess" x_0 and then form a sequence of numbers by x_1= f(x_0)/f'(x_0), x_2= f(x_1)/f'(x_2), ....
Here your function is f(x)= e^(x/3)  0.05471*x. What is f'(x)?
The problem asks that you set x_0 to "the endpoint (of [2.5, 2.9]) having the smallest value of f".
Okay, what is f(2.5)? What is f(2.9)?