Hi, I am Vijay from india. My user name is vijaysingh. I have completed my graduate. My interest area is mathematics
Hi anybody please help me
onsider Efron’s non-transitive dice where the 6 faces as are in the table below.
Die A 0 0 4 4 4 4
Die B 3 3 3 3 3 3
Die C 2 2 2 2 6 6
Die D 1 1 1 5 5 5
Suppose there are four players in the game and each will choose one die and roll it. The person
who rolls the smallest number will be eliminated. For each die, calculate the probability that
the smallest number observed occurs on that die. Now which die would you choose (assuming
you want to stay in the game rather than reading a good book, having root canal work, etc.)?
For die A the probability of "0" is 1/3, for "4", 2/3.
For die B the probability of "3" is 1.
For die C the probability of "2" is 2/3, for "6" is 1/3.
For die D the probability of "1" is 1/2, for "5" is 1/2.
If A is a "0", which has probability 1/3, it is certain to be lowest. If A is a "4", which has probability 2/3, it cannot be lowest since B will be "3".
The probability A is lowest is 1/3.
B must roll "3" and that will be lowest if A is "4" (probabililty 2/3), C is "6" (probability 1/3), and D is "5" (probability 1/2). The probability of all those is (2/3)(1/3)(1/2)= 1/9.
Can you do the same calculation for dice C and D?
can anyone answer this plz on a monday or a thursday mr gibson paints a masterpiece with a probaliity of 1/5. on anyother day the probability of producing a master piece is 1/100 gibson never knows the day, find the probability that on 1 day chosen at random he will pain a masterpiece