help with math word problem

one elevator leaves first floor of a building at 9:00 a.m. It takes 5 seconds to travel between floors, stays 10 seconds at each floor and stops at each floor on its way to the top. Another elevator leaves the 12th (top) floor at 9:00 a.m. ; it takes 5 seconds to travel between floors, stays 15 seconds at each floor and stops at each floor on its way to the bottom. On what floor will both elevators be available at the same time?

Re: help with math word problem

I am guessing it would be somewhere in the middle, 6th or 7th floor but cannot prove it mathematically yet.

Re: help with math word problem

Let they meet on x th floor.

upward lift takes 5 + 10 = 15 s per floor

downward lift takes 5 + 15 = 20 s per floor

if they do not wait at each floor,

then time taken by upward lift = 5x

and time taken by downward lift = 5(12 – x)

5x = 5(12 – x)

x = 6 th floor

as they are waiting

then time taken by upward lift = (5 + 10)x = 15x

and time taken by downward lift = (5 + 15)(12 – x) = 20(12 – x)

15x = 20(12 – x)

35x = 240

x = 6.86 th floor

in between 6 and 7 th floor

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Re: help with math word problem