Hello
3 log x - log4y
What is this expression simplified?
1. I assume that you mean
$\displaystyle 3\cdot \log(x) - \log(4y)$
2. If you want to use logarithms in the simplest form then you'll get:
$\displaystyle 3\cdot \log(x) - \log(4) -\log(y)$
3. If you want to collect these terms to one logarithm then you'll get:
$\displaystyle 3\cdot \log(x) - \log(4y) = \log\left(\frac{x^3}{4y}\right)$
There are many ways of solving this.
one among them is,
½ log4x2+1/3 log4y (1/2 log x squared to the base 4 + 1/3 log y to the base 4) *4 is the base.
In other way,
-logx+ 2 log(x-1)+3 logx 2
That's -logx+2 (x-1)+3logx squared.
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