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Math Help - A simple maths question-simplifying

  1. #1
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    A simple maths question-simplifying

    Hello

    3 log x - log4y

    What is this expression simplified?
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  2. #2
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    Re: A simple maths question-simplifying

    Quote Originally Posted by maddie12131 View Post
    Hello

    3 log x - log4y

    What is this expression simplified?
    1. I assume that you mean

    3\cdot \log(x) - \log(4y)

    2. If you want to use logarithms in the simplest form then you'll get:

    3\cdot \log(x) - \log(4) -\log(y)

    3. If you want to collect these terms to one logarithm then you'll get:

    3\cdot \log(x) - \log(4y) = \log\left(\frac{x^3}{4y}\right)
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  3. #3
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    Re: A simple maths question-simplifying

    Thankyou buddy...it was the last one by the way.
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  4. #4
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    Re: A simple maths question-simplifying

    There are many ways of solving this.
    one among them is,
    log4x2+1/3 log4y (1/2 log x squared to the base 4 + 1/3 log y to the base 4) *4 is the base.
    In other way,
    -logx+ 2 log(x-1)+3 logx 2
    That's -logx+2 (x-1)+3logx squared.




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