Hello

3 log x - log4y

What is this expression simplified?

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- Feb 1st 2013, 11:03 PMmaddie12131A simple maths question-simplifying
Hello

3 log x - log4y

What is this expression simplified? - Feb 2nd 2013, 11:59 AMearbothRe: A simple maths question-simplifying
1. I assume that you mean

$\displaystyle 3\cdot \log(x) - \log(4y)$

2. If you want to use logarithms in the simplest form then you'll get:

$\displaystyle 3\cdot \log(x) - \log(4) -\log(y)$

3. If you want to collect these terms to one logarithm then you'll get:

$\displaystyle 3\cdot \log(x) - \log(4y) = \log\left(\frac{x^3}{4y}\right)$ - Feb 2nd 2013, 11:07 PMmaddie12131Re: A simple maths question-simplifying
Thankyou buddy...it was the last one by the way.

- Feb 4th 2013, 08:13 PMjohnykeetsRe: A simple maths question-simplifying
There are many ways of solving this.

one among them is,

½ log4x2+1/3 log4y (1/2 log x squared to the base 4 + 1/3 log y to the base 4) *4 is the base.

In other way,

-logx+ 2 log(x-1)+3 logx 2

That's -logx+2 (x-1)+3logx squared.

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