This is first post, will I be able to post in the normal section after this?
EDIT: ^Ignore :P I figured it out.
Anyway, one of my homework problems reads like this
"Verify that y = -tcos(t)-t is a solution to the initial value problem
t(dy/dt) = y + sin(t); y(pi)=0"
I solved it,
dy/dt = (-tcos(t)-t)' = t(sin(t))-cos(t)-1
After plugging y and y' in,
t(tsin(t) - cos(t) - 1) = (-tcos(t) - t) + t2sin(t)
t2sin(t) - tcos(t) - t = t2sin(t) - tcos(t) - t
-tcos(t) - t = -tcos(t) - t
But my question is, why did they give me the information that y(pi) = 0? Although it's true, am I supposed to use it anywhere? Is it just extra info. to throw me off?