angle ø = 2π/3 × 180/π = 120°

wetted perimeter = °ø/360 × 2πr

= 120/360 × 2π × 12 = 8π

area of cross section = ø/360 ×πr²

= 120/360 × π × 12 × 12 = 48π

volume of water = ø/360 × πr² L

= 120/360 × π × 12 × 12 × (0.7 × 100) length converted in cm

= 3.36π cm³

angle of dry perimeter = (360 – 120) = 240°

----