for x> 0 and y> 0 > . how do I find out whats equivalent to the square root of 16x^9 y^36?
My answer is 4y^18x^4 square root x
Is that correct? I think I did something wrong
for x> 0 and y> 0 > . how do I find out whats equivalent to the $\displaystyle \sqrt{ 16x^9 y^{36}}$?
My answer is $\displaystyle 4y^{18}x^4\sqrt x$
Is that correct? I think I did something wrong