1. ## Square root

for x> 0 and y> 0 > . how do I find out whats equivalent to the square root of 16x^9 y^36?
My answer is 4y^18x^4 square root x
Is that correct? I think I did something wrong

2. ## Re: Square root

Originally Posted by tahirakw
for x> 0 and y> 0 > . how do I find out whats equivalent to the $\sqrt{ 16x^9 y^{36}}$?
My answer is $4y^{18}x^4\sqrt x$
Is that correct? I think I did something wrong
Yes that is correct

Thanks